Let's work through a PSAT problem. (Click on any of the images to make them bigger).
First, let's find the equation of the parabola by putting the coordinate for the vertex into a vertex-form quadratic equation, y = a(x-h)2 + k, where the vertex is (h, k).
We need to find a, so let's use the other point given on the parabola (0,3) and plug it in the equation.
Let's put that back in the quadratic equation.
Now we need to find the equation of the linear function. First we'll find the slope of the line, and then we'll use the y-intercept of the line to complete the equation.
Now we need to solve the system of equations. We can find the solutions (the two places they touch) by setting both equations equal to each other.
Let's solve.
Since we want the point that's on the right side of the y-intercept, we know that x is going to be positive, so the answer we want is 6. v, which is representing the x-coordinate of the solution of the system of equations, is 6.